Question #cbd0e

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Question #cbd0e

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Answer 1 · 2017-02-15T03:15:41

see explanation.

Explanation:

$s i x (x) = \frac{1}{2}$ $six (x) = 1/2$
$x = \frac{π}{6} or 30^{o}$ $x = pi/6 or 30^o$

since $sin (x)$ $sin (x)$ is a positive value, it lie in 1st and 2nd quadrant only.

Therefore,

1st quadrant,
$x = \frac{π}{6} or 30^{0}$ $x=pi/6 or 30^0$
$x = (2 π + \frac{1}{6} π) = \frac{13}{6} π or (360^{o} + 30^{0}) = 390^{0}$ $x=(2pi+1/6 pi)=13/6 pi or (360^o + 30^0) = 390^0$
In 1st quadrant, $x = \frac{π}{6} and \frac{13}{6} π$ $x = pi /6 and 13/6 pi$

2nd quadrant,
$x = \frac{5}{6} π or (180^{o} - 30^{0}) = 150^{o}$ $x=5/6 pi or (180^o-30^0) = 150^o$
$x = (2 π + \frac{5}{6} π) = \frac{17}{6} π or (360^{o} + 150^{0}) = 510^{o}$ $x=(2 pi+5/6 pi) = 17/6 pi or (360^o + 150^0) = 510^o$
In 2nd quadrant, $x = \frac{5}{6} π and \frac{17}{6} π$ $x=5/6 pi and 17/6 pi$

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Question #cbd0e

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