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Question #2d564

1 Answer

Feb 10, 2017

$(del^2f)/dx^2 = y^2e^(xy)$

Explanation:

$f(x,y) = (e^x)^y = e^(xy)$

$(delf)/ dx= ye^(xy)$

$(del^2f)/dx^2 = y^2e^(xy)$

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