Question #2fa3d

1 Answer
P dilip_k
Feb 12, 2017

(− sec ( x ) tan^2 ( x ) − ( 9 − sec ( x ) ) sec^2 ( x ))/tan^2 x

=(− sec ( x ) (sec^2 ( x ) -1)− ( 9 − sec ( x ) ) sec^2 ( x ))/tan^2 x

=(− sec^3 ( x )+ secx− 9sec^2x + sec^3 ( x ))/tan^2 x

=(secx− 9sec^2x )/tan^2 x

=secx/tan^2x− (9sec^2x)/tan^2 x

=cosx xxcsc^2x− 9csc^2x

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