If $P (x) = x^{3} + 13 x^{2} - 8 x + 20$ $P(x)=x^3+13x^2-8x+20$ what is the value of $P (x 0$ $P(x0$ when $x = 1$ $x=1$ ?

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If $P (x) = x^{3} + 13 x^{2} - 8 x + 20$ $P(x)=x^3+13x^2-8x+20$ what is the value of $P (x 0$ $P(x0$ when $x = 1$ $x=1$ ?

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Answer 1 · 2017-02-13T13:24:59

$P (- 1) = 40$ $P(-1)=40$

Explanation:

If $P (x) = x^{3} + 13 x^{2} - 8 x + 20$ $P(color(red)x)=color(red)x^3+13color(red)x^2-8color(red)x+20$
then
$XX P (- 1) = {(- 1)}^{3} + 13 \cdot {(- 1)}^{2} - 8 \cdot (- 1) + 20$ $color(white)("XX")P(color(red)(-1))=(color(red)(-1))^3+13 * (color(red)(-1))^2 - 8 * (color(red)(-1))+20$

$XXXXXX = - 1 + 13 + 8 + 20$ $color(white)("XXXXXX")=-1 +13+8 +20$

$XXXXXX = 40$ $color(white)("XXXXXX")=40$

Answer 2 · 2017-02-13T13:25:31

$40$ $40$

Explanation:

To evaluate P(-1), substitute x = - 1 in P(x)

$\Rightarrow P (- 1) = {(- 1)}^{3} + 13 {(- 1)}^{2} - 8 (- 1) + 20$ $rArrP(color(red)(-1))=(color(red)(-1))^3+13(color(red)(-1))^2-8(color(red)(-1))+20$

$= - 1 + 13 + 8 + 20$ $=-1+13+8+20$

$= 40$ $=40$

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If $P (x) = x^{3} + 13 x^{2} - 8 x + 20$ $P(x)=x^3+13x^2-8x+20$ what is the value of $P (x 0$ $P(x0$ when $x = 1$ $x=1$ ?

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Explanation:

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If P(x)=x3+13x2−8x+20P(x)=x^3+13x^2-8x+20 what is the value of P(x0P(x0 when x=1x=1?

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Explanation:

Explanation:

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If $P (x) = x^{3} + 13 x^{2} - 8 x + 20$ $P(x)=x^3+13x^2-8x+20$ what is the value of $P (x 0$ $P(x0$ when $x = 1$ $x=1$ ?