Question #b7d22

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Feb 13, 2017

Given
$y = {sin}^{3} 5 x$ $y=sin^3 5x$
Using chain rule to calculate derivative
$y'=d/dx(sin^3 5x)$
$=>y'=(3sin^2 5x)(cos5x)(5)$
$=>y'=15sin^2 5xcos5x$

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Question #b7d22

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