Simplify $(cscx-sinx)/(sinxcscx)$ ?

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Answer 1 · 2017-02-14T04:54:45

Please see below.

$(cscx-sinx)/(sinxcscx)$

= $(cscx-sinx)/(sinx xx1/sinx)$

= $(cscx-sinx)/(cancelsinx xx1/cancelsinx)$

= $(cscx-sinx)/1$

= $cscx-sinx$

= $1/sinx-sinx$

= $(1-sin^2x)/sinx$

= $cos^2x/sinx$

= $cotscscx$

Simplify (cscx-sinx)/(sinxcscx)(cscx-sinx)/(sinxcscx)?