Question #2e707

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Answer 1 · 2017-02-16T05:57:45

$LHS=(1-sinv)/cosv+cos/(1-sinv)$

$=(1-sinv)/cosv+((1+sinv)cosv)/((1-sinv)(1+sinv))$

$=(1-sinv)/cosv+((1+sinv)cosv)/(1-sin^2v)$

$=(1-sinv)/cosv+((1+sinv)cosv)/cos^2v$

$=(1-sinv)/cosv+(1+sinv)/cosv$

$=(1-sinv+1+sinv)/cosv$

$=2/cosv=2secv=RHS$

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