Question #7bb02

1 Answer
A08
Feb 17, 2017

Given expression is
y= 3e^x+ 4/(root(3)(x)
=>y= 3e^x+ 4(x)^(-1/3)
Differentiating
y'= d/dx(3e^x+ 4(x)^(-1/3))
=>y'= d/dx(3e^x)+ d/dx(4(x)^(-1/3))
=>y'= 3e^x+ 4xx(-1/3)(x)^(-1/3-1)
=>y'= 3e^x- 4/3(x)^(-4/3)
=>y'= 3e^x- 4/(3(x)^(4/3))
=>y'= 3e^x- 4/(3root(3)(x^4)

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