Question #586ed

1 Answer
Jim G.
Dec 11, 2017

x~~0.668" to 3 dec. places"

Explanation:

5e^(2x)+1=20

rArr5e^(2x)=19

rArre^(2x)=19/5

•color(white)(x)logx^nhArrnlogx

"take the ln (natural log ) of both sides"

lne^(2x)=ln(19/5)

rArr2xcancel(lne)^1=ln(19/5)

rArrx=(ln(19/5))/2~~0.688" to 3 dec. places"

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