The larger number LL is 1111 more or +11+11 than twice the smaller SS number or 2 xx S2×S.
That means L = 2S + 11L=2S+11.
Now 33 times the larger or 3 xx L3×L is 99 more or + 9+9 than 77 times the smaller or 7S7S.
That means 3L = 7S + 93L=7S+9.
We can multiply both sides of the first equation by 33 so it will match the second equation for the LL term.
3L = 6S +333L=6S+33
We can now substitute the value of 3L3L into the second equation:
6S + 33 = 7S + 96S+33=7S+9
Subtract SS values from the right side and number values from the right side to bring them across the == sign.
-S = -24−S=−24
S = 24S=24
Using the first equation to solve for LL;
L = 2S + 11L=2S+11
L = 2(24) + 11L=2(24)+11
L = 59L=59
To check, substitute the values back into the second equation:
3L = 6S + 93L=6S+9
177 = 168 + 9177=168+9
177 = 177177=177
