Question #d36b2
1 Answer
Explanation:
As you know, the density of a substance tells you the mass of exactly one unit of volume of that substance.
In your case, liquid bromine is said to have a density of
color(blue)(color(purple)("3.102 g") color(white)(.)"mL"^(-1)) -> color(purple)("3.102 g")color(white)(.) color(black)("for every") color(white)(.)color(blue)("1 mL")color(white)(.)"of liquid Br"_23.102 g.mL−1→3.102 g.for every.1 mL.of liquid Br2
Now, your goal here is to figure out the volume of liquid bromine that would contain
Bromine has a molar mass of
In your case, the sample of liquid bromine will have a mass of
0.295 color(red)(cancel(color(black)("moles Br"_2))) * "159.808 g"/(1color(red)(cancel(color(black)("moles Br"_2)))) = "47.14 g"
You can now use the density of liquid bromine as a conversion factor to determine exactly how many milliliters of bromine would have a mass of
47.14 color(red)(cancel(color(black)("g"))) * color(blue)("1 mL")/(color(purple)(3.102)color(red)(cancel(color(black)("g")))) = color(darkgreen)(ul(color(black)("15.2 mL")))
The answer is rounded to three sig figs, the number of significant figures you have for the number of moles of bromine present in the sample.
