A solution has a mass of $498g$ , and a volume of $1.2L$ . What is its density in units of $g*mL^-1$ ?

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Answer 1 · 2017-02-22T18:42:21

$rho,$ $"density"$ $=$ $"Mass"/"Volume"$

In your example, $rho=("Mass")/("Volume")=(598*g)/(1.2*cancelLxx10^(3)*mL*cancel(L^-1))$ $=$ $0.498*g*mL^-1$ .

Is the solution likely to be aqueous? Why or why not?

A solution has a mass of 498*g498*g, and a volume of 1.2*L1.2*L. What is its density in units of g*mL^-1g*mL^-1?