Question #32b3c Precalculus Geometry of a Parabola Vertex Form of the Equation 1 Answer Vinícius Ferraz Feb 24, 2017 y = 5x^2 + 20x + 17 Explanation: y = ax^2 + bx + c a(-1)^2 + b(-1) + c = 2 x_V = -2 = -b/(2a) y_V = -3 = - Delta / (4a) b = 4a 3 = ((4a)^2 - 4ac)/(4a) Rightarrow 3 = 4a - c Rightarrow c = 4a - 3 a -b + c = 2 a - 4a + 4a - 3 = 2 Rightarrow a = 5 b = 4*5, c = 4*5 - 3 Answer link Related questions How do I convert the equation f(x)=x^2+1 to vertex form? How do I convert the equation f(x)=x^2+2/5x−1 to vertex form? How do I convert the equation f(x)=x^2-4x+3 to vertex form? How do I convert the equation f(x)=x^2-8x+15 to vertex form? How do I convert the equation f(x)=x^2+6x+5 to vertex form? How do I convert the equation f(x)=x^2-2x-3 to vertex form? What do h and k represent in the vertex form of a parabola's equation? How do I find the vertex of y=(x−3)^2+4? How do I find the vertex of y=(x+2)^2-3? How do I find the vertex of y=(x+7)^2? See all questions in Vertex Form of the Equation Impact of this question 2007 views around the world You can reuse this answer Creative Commons License