How do you factorize $204 x^{2} + 100 y^{2} + 64$ $204x^2+100y^2+64$ ?

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Answer 1 · 2017-02-28T04:57:00

$204 x^{2} + 100 y^{2} + 64 = 4 (51 x^{2} + 25 y^{2} + 16)$ $204x^2+100y^2+64=4(51x^2+25y^2+16)$

In the polynomial $204 x^{2} + 100 y^{2} + 64$ $204x^2+100y^2+64$ , we have no variable common between the three monomials forming the polynomial.

However, the coefficients $204$ $204$ and $100$ $100$ and constant term $64$ $64$ have HCF as $4$ $4$

and hence $204 x^{2} + 100 y^{2} + 64$ $204x^2+100y^2+64$

= $4 \times 51 x^{2} + 4 \times 25 y^{2} + 4 \times 16$ $4xx51x^2+4xx25y^2+4xx16$

= $4 (51 x^{2} + 25 y^{2} + 16)$ $4(51x^2+25y^2+16)$

How do you factorize 204x2+100y2+64204x^2+100y^2+64?