What is the derivative of $ln3x$ ?

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Answer 1 · 2017-02-26T20:17:17

$dy/dx=1/x$

We will need the standard result:

$d/dx lnx=1/x$

By the rule of logs:

$y=ln3x$
$\ \ \=ln3+lnx$

$:. dy/dx=0+1/x = 1/x$

Or we can implicitly apply the chain rule:

$dy/dx = 1/(3x) * 3 = 1/x$

What is the derivative of ln3xln3x?