If $5^{x + 2} = 4$ $5^(x+2)=4$ , find $x$ $x$ ?

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Answer 1 · 2017-03-14T16:42:05

$x = - 1.1386$ $x=-1.1386$

As $5^{(x + 2)} = 4$ $5^((x+2))=4$

$(x + 2) log 5 = log 4$ $(x+2)log5=log4$

i.e. $x + 2 = \frac{log 4}{log 5} = \frac{0.60206}{0.69897}$ $x+2=log4/log5=0.60206/0.69897$

i.e. $x + 2 = 0.8614$ $x+2=0.8614$

and hence $x = 0.8614 - 2 = - 1.1386$ $x=0.8614-2=-1.1386$

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