Question #ef8ed

1 Answer
Jim G.
Mar 1, 2017

1/9

Explanation:

For color(blue)"2 perpendicular lines"

"with slopes "m_1" and "m_2

"then " color(red)(bar(ul(|color(white)(2/2)color(black)(m_1xxm_2=-1)color(white)(2/2)|)))

rArr-9xxm_2=-1

rArrm_2=(-1)/(-9)=1/9larrcolor(red)" slope of other line"

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