Question #ceaab

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Question #ceaab

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Answer 1 · 2017-02-28T21:08:24

Average velocity for trip: $\approx 71 km/hr$ $approx 71 "km/hr"$

Explanation:

A car moves due east at 93 km/hr for 64 minutes and then turns around and moves west at 72 km/hr for 10 minutes, what is the average velocity for the entire trip?

Distance travelled in E direction:

$93 \cdot \frac{64}{60}$ $93*64/60$ km

Distance travelled back in W direction:

$72 \cdot \frac{10}{60}$ $72*10/60$ km

Net travel ( ie displacement ) in E direction is:

$93 \cdot \frac{64}{60} - 72 \cdot \frac{10}{60}$ $93*64/60 - 72*10/60$ km

$= \frac{436}{5}$ $=436/5$ km $= 87.2$ $= 87.2$ km

Time for entire trip: $64 + 10 = 74min = 74/60 hr$

Average velocity for trip $= "displacement"/"time"$

$= 87.2/(74/60) approx 70.702 "km/hr"$

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Question #ceaab

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