How do we simplify $sintheta/sin(theta + pi/2)$ ?

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Answer 1 · 2017-03-04T15:52:25

The expression equals $tantheta$ .

We can expand the denominator using $sin(A + B) = sinAcosB + sinBcosA$ .

$sintheta/(sinthetacos(pi/2) + sin(pi/2)costheta)$

$sintheta/((0)sin theta + 1(costheta)$

$sintheta/costheta$

Use $tantheta = sintheta/costheta$ :

$tantheta$

Hopefully this helps!

How do we simplify sintheta/sin(theta + pi/2)sintheta/sin(theta + pi/2)?