Question #d280e

Question

Question #d280e

1 Answer

Impact of this question

1450 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-26T00:33:58

$1000 m$ $1000m$

Explanation:

Distance traveled $s$ $s$ in time $t$ $t$ . Applicable kinematic equation is
$s = u t + \frac{1}{2} a t^{2}$ $s=ut+1/2at^2$
where $a$ $a$ is acceleration and $u$ $u$ is initial velocity.

Car a
$s_{a} = 0 \times 60 + \frac{1}{2} (0.75) {(60)}^{2}$ $s_a=0xx60+1/2(0.75)(60)^2$
$s_{a} = 1350 m$ $s_a=1350m$

Car b
$s_{b} = 0 \times 60 + \frac{1}{2} (0.25) {(60)}^{2}$ $s_b=0xx60+1/2(0.25)(60)^2$
$s_{a} = 450 m$ $s_a=450m$

Difference is $= 1350 - 450 = 900 m$ $=1350-450=900m$
When cars started Car a was ahead of Car b by $= 100 m$ $=100m$
After $1min$ Car a is ahead of Car b by $=900+100m=1000m$

Science

Math

Humanities

... and beyond

Question #d280e

1 Answer

Explanation:

Related questions

Impact of this question