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Question #142e0

1 Answer

Ratnesh Bhosale

Mar 8, 2017

$rArr costheta = 5/sqrt61$

Explanation:

$tan theta= -6/5$

Using the identity in trigonometry,
$1 + tan^2 theta= sec^2theta$

$rArr 1+36/25= sec^2theta$

$rArr 61/25= sec^2theta$

$rArr sectheta = sqrt61/5$

Also, $cos theta= 1/sec theta$

$rArr costheta = 5/sqrt61$

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