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Question #fb6c4

1 Answer

Mar 9, 2017

The vertex is at $(- 5, - 16)$ $(-5,-16)$

Explanation:

$x^{2} + 10 x + 9$ $x^2 +10x +9$

$= x^{2} + 10 x + 25 + 9 - 25 \pm \frac{b^{2}}{2}$ $= x^2 +10x +25 +9-25" "+-b^2/2$

$= {(x + 5)}^{2} - 16$ $= (x +5)^2 -16$

This is in the form ${(x + b)}^{2} + c$ $(x+b)^2 +c$

The vertex is at $(- 5, - 16)$ $(-5,-16)$

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