Question #e4bf6

1 Answer
Mar 12, 2017

x=0, pi/2, pi, (3pi)/2
x=(3 pi)/8, (7pi)/8, (11pi)/8, (15pi)/8

Explanation:

(sec2x)^2 -1equals (tan 2x)^2. The given equation thus becomes tan 2x (tan 2x +1)=0

It is thus tan 2x=0 or tan 2x= -1

Tan 2x=0 gives 2x=0, pi, 2pi,3pi that is x=0, pi/2, pi, (3pi)/2

Tan 2x=-1, gives 2x= (3pi)/4, (7pi)/4, (11pi)/4, (15pi)/4, so that

x=(3 pi)/8, (7pi)/8, (11pi)/8, (15pi)/8