Simplify $(tan(theta-beta)+tanbeta)/(1-tan(theta-beta)tanbeta)$ ?

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Answer 1 · 2017-03-15T08:34:02

Please see below.

Recall $tan(A+B)=(tanA+tanB)/(1-tanAtanB)$ ............(1)

Let $A=theta-beta$ and $B=beta$

and then $A+B=theta-beta+beta=theta$

putting these in (1)

$(tan(theta-beta)+tanbeta)/(1-tan(theta-beta)tanbeta)= tantheta$

Simplify (tan(theta-beta)+tanbeta)/(1-tan(theta-beta)tanbeta)(tan(theta-beta)+tanbeta)/(1-tan(theta-beta)tanbeta)?