How do you find two numbers which differ by 5, such that twice the first number less three times the second will give an answer of $2$ ?

Question

1593 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-16T17:37:50

The second number is $8$ and the first number is $13$

Write an expression for each of the numbers in terms of $x$ and then make an equation.

Let the second number be $x$ .
The first number is $x+5$

Twice the first, less three times the second $=2$

$2(x+5)-3(x) = 2$

$2x +10 -3x = 2$

$10-2 = 3x -2x" "larr$ to keep the values positive.

$8 = x$

The second number is $8$ and the first number is $13$

Check:

$2xx13 - 3xx8 = 26-24 = 2$
Checks out fine!

How do you find two numbers which differ by 5, such that twice the first number less three times the second will give an answer of 22?