Solve for $x$ $x$ and $y$ $y$ , given that $x + 8 y = 160$ $x+8y=160$ and $3 x + 5 y = 119$ $3x+5y=119$ ?

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Answer 1 · 2017-03-19T05:50:17

$y = 19 and x = 8$ $y=19 and x=8$

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$x + 8 y = 160$ $x+8y=160$
$3 x + 24 y = 480$ $3x+24y=480$ $\to$ $->$ ①

$3 x + 5 y = 119$ $3x+5y=119$ $\to$ $->$ ②

From ① $-$ $-$ ②,

$3 x + 24 y - 3 x - 5 y = 480 - 119$ $3x+24y-3x-5y=480-119$
$19 y = 361$ $19y=361$
$y = 19$ $y=19$

$x = 160 - (19 \times 8)$ $x=160-(19×8)$
$x = 8$ $x=8$

Hence, $x = 8 and y = 19$ $x=8 and y=19$ .

Solve for xxx and yyy, given that x+8y=160x+8y=160x+8y=160 and 3x+5y=1193x+5y=1193x+5y=119?