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Question #42f0e

1 Answer

Apr 29, 2017

$y'=-sinx lnsqrtx+frac{cosx}{2x}$

Explanation:

$y=(cosx)(lnsqrtx)$

Using the product rule:
$y'=(-sinx)(lnsqrtx)+(cosx)(frac{1/2x^(-1/2)}{x^(1/2)})$

$y'=-sinx lnsqrtx+frac{cosx}{2x}$

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