Question #55104

1 Answer
Mar 22, 2017

Sinx /(1+cosx )+ (1+cosx) / sinx

=(Sinx(1-cosx)) /((1+cosx )(1-cosx))+ (1+cosx) / sinx

=(Sinx(1-cosx)) /(1-cos^2x) + (1+cosx) / sinx

=(Sinx(1-cosx)) /sin^2x + (1+cosx) / sinx

=(1-cosx) /sinx + (1+cosx) / sinx

=1/sinx-cosx/sinx + 1/sinx+cosx/ sinx

=2/sinx=2cscx