Question

Question #d6127

Answer 1

`x = 0, pi, 7/6 pi, 11/6 pi and 2 pi` for `0<= x <= 2pi`

Explanation:

`2 sin^2 x + sin x = 0`

`sin x (2 sin x + 1) = 0`

`sin x = 0` and `2 sin x + 1= 0 -> sinx =-1/2`

`sin x = 0 -> x =0^@, 180^@, 360^@,.. = 0pi, 1pi, 2pi,...`

`sin x =-1/2 -> x = 210^@, 330^@, 570^@,, = 7/6 pi, 11/6 pi, 19/6 pi ..`