Question

Question #4e523

Answer 1

`dy/dx=2x`

Explanation:

Consider the term `e^(-3lnx)`

`" Now " color(red)(bar(ul(|color(white)(2/2)color(black)(e^(ln(f(x))=f(x))color(white)(2/2)|))))larr" inverse functions"`

`color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx^nhArrnlogx)color(white)(2/2)|)))`

`rArre^(-3lnx)=e^(lnx^-3)=x^-3`

`rArry=x^5e^(-3lnx)=x^5xxx^-3=x^2`

`rArrdy/dx=2x`