Question #f1a06 Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer salamat Mar 29, 2017 sin = sqrt 56/9, cos = 5/9, and tan = sqrt 56/5 Explanation: sec = 1/cos = 9/5, = 5/9 based on pyhtogoras theoram for triangle, sin = sqrt(9^2 - 5^2)/9 = sqrt 56/9, and tan = sqrt 56/5, we also can use sin/cos Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If sec theta = 4, how do you use the reciprocal identity to find cos theta? How do you find the domain and range of sine, cosine, and tangent? What quadrant does cot 325^@ lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that 1+tan^2 theta = sec ^2 theta? See all questions in Relating Trigonometric Functions Impact of this question 1379 views around the world You can reuse this answer Creative Commons License