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Answer 1 · 2017-03-31T01:42:39

$RHS= cosx - tanx/cscx$

$= cosx - (sinx/cosx)/(1/sinx)$

$= cosx - (sinx/cosx)xx(sinx/1)$

$= cosx - sin^2x/cosx$

$= (cos^2x - sin^2x)/cosx$

$= (cos^2x - 1+cos^2x)/cosx$

$= (2cos^2x - 1)/cosx$

$= (2cos^2x)/cos^2x - 1/cosx$

$= 2cosx - secx=LHS$

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