Question

Question #988dd

Answer 1

`ZnCl_2 + Na_2CO_3 rarr ZnCO_3 + 2 NaCl`

Explanation:

`ZnCl_2 + Na_2CO_3 rarr ZnCO_3 + NaCl`

This is what I do...
I write that all elements on the reactant side as well as those on the product side. Not forgetting to split them when there is an addition.

Reactants

`Zn=1`
`Cl=2`
`+`
`Na=2`
`C=1`
`O=3`

Products

`Zn=1`
`C=1`
`O=3`
`+`
`Na=1xxcolor(red)2=2`
`Cl=1xxcolor(red)2=2`

From the above, we see that `Na` is `2` on the reactant side and `1` on the product side so we multiply by `color(red)2` to make it equal. When you do this, it automatically affects `Cl` because it forms a compound.

Check to see if all elements are balanced then rewrite the equation.

`ZnCl_2 + Na_2CO_3 rarr ZnCO_3 + color(red)2 NaCl`