Question #cf8dc

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Question #cf8dc

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Answer 1 · 2017-04-04T01:29:08

${(sin x + cos x)}^{2} = {sin}^{2} x + {cos}^{2} x + 2 sin x . cos x$ $(sin x + cos x)^2 = sin^2 x + cos^2 x + 2sin x.cos x$
Since,
${sin}^{2} x + {cos}^{2} x = 1$ $sin^2 x + cos^2 x = 1$
$2 sin x . cos x = sin 2 x$ $2sin x.cos x = sin 2x$ ,
Therefore,
${(sin x + cos x)}^{2} = 1 + sin 2 x$ $(sin x + cos x)^2 = 1 + sin 2x$

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