Question

Question #935d4

Answer 1

`(2x^3y^3)/(6x^-4y^4) = x^7/(3y)`

Explanation:

Given: `(2x^3y^3)/(6x^-4y^4)`

We can see the integer multipliers: `2/6=1/3`

The `x` component is `x^3/x^-4= x^3/(1/x^4)=x^7` `->`after invert and multiply

The `y` component is `y^3/y^4=1/y` `->`dividing exponents = subtract

Then we can multiply all the components:

`(2x^3y^3)/(6x^-4y^4) = (1/3)x^7(1/y) = x^7/(3y)`