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Question #57682

1 Answer

Apr 16, 2017

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Explanation:

$y = arcsin (cot (x^{- 2}))$ $y=arcsin(cot(x^-2))$

$sin y = cot (x^{- 2})$ $siny=cot(x^-2)$

$(cosy)y'=-(2csc^2(x^-2))/x^3$

$y'=-(2csc^2(x^-2))/(x^3cosy)$

$cosy=+-sqrt(1-sin^2y)=+-sqrt(1-cot^2(x^-2))$

$y'=+-(2csc^2(x^-2))/(x^3sqrt(1-cot^2(x^-2)))$

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