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Question #65677

1 Answer

Apr 12, 2017

$x > \frac{4}{5}$ $x > 4/5$

Explanation:

$9^{x - 2} > {(\frac{1}{27})}^{x}$ $9^(x-2) > (1/27)^x$

${(3^{2})}^{x - 2} > {(\frac{1}{3^{3}})}^{x}$ $(3^2)^(x-2) > (1/(3^3))^x$

$3^{2 x - 4} > 3^{- 3 x}$ $3^(2x-4) > 3^(-3x)$

therefore,
$(2 x - 4) > (- 3 x)$ $(2x-4) > (-3x)$

$5 x > 4$ $5 x > 4$
$x > \frac{4}{5}$ $x > 4/5$

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