Question #5cc93

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Answer 1 · 2017-04-15T01:54:37

$x=1/3$

$x=-2/3+-i$

Subtract $13$ from both sides

$27x^3+27x^2+27x-13=0$

This can factored

$(3x-1)(9x^2+12x+13)=0$

So,

$3x-1=0$

$3x=1$

$x=1/3$

$9x^2+12x+13=0$

$(-12+-sqrt((12)^2-4(9)(13)))/(2(9))$

$(-12+-sqrt(144-468))/18$

$(-12+-sqrt(324)i)/18$

$-12/18+-(18i)/18$

$-2/3+-i$