Question

Question #40df4

Answer 1

Solution: In `0<2a<2pi , a ~~ 9.74^0 ,80.27^0`

Explanation:

`3(1-cos2a) =tana or 3(1- (cos^2a-sin^2a)) =sina/cosa` or

`3(1-cos^2a+sin^2a) = sina/cosa or 3(2sin^2a) =sina/cosa` or

`6sin^2a =sina/cosa or 6sina =1/cosa or 6sina*cosa=1 or 3*sin2a =1 or sin2a =1/3 or 2a = sin^-1 (1/3) ~~19.47^0 or a ~~ 9.74^0`

In `0<2a<2pi` Also `2a= pi-2a=180- 19.47=160.53^0:. a= 160.53/2=80.27`

Solution: In `0<2a<2pi , a ~~ 9.74^0 ,80.27^0` [Ans]