Question

Question #dbdd7

Answer 1

The relative atomic mass of the sample of lead is 208.

Explanation:

You have the equation

`M_text(r):color(white)(mmml)xcolor(white)(ml)35.45color(white)(mm) x "+70.90"`
`color(white)(mmmmm)"Pb" + "2Cl" →color(white)(ml) "PbCl"_2`
`"Mass/g:" color(white)(ml)1color(white)(mll)0.341color(white)(mmll) 1.341`

`"Mass of Cl = 1.341 g - 1 g = 0.341 g"`

We can set up the ratio

`(1 color(red)(cancel(color(black)("g Pb")))}/(0.341 color(red)(cancel(color(black)("g Cl")))) = (x color(red)(cancel(color(black)("g Pb"))))/(70.90 color(red)(cancel(color(black)("g Cl"))))`

`x = 70.90/0.341 = 208`

`M_text(r) = 208`