What is the thickness of an iron plate that has a mass of $0.25g$ , and an area of $25cm^2$ . $rho_"iron"=19gcm^-2$ ?

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Answer 1 · 2017-05-15T12:50:48

$"Thickness"~=0.005*mm$

I think you are one the right track........

$rho_"density"="mass"/"volume"$

And of course, $"volume"=lxxbxxw$ , where $l="length"$ , $b="breadth"$ , and $w="width"$ ( $"lbw"!="leg before wicket"$ ).

So, $"volume"="mass"/rho_"density"=lxxbxxw$

And thus $w("width")="mass"/(rhoxxlxxb)$

$=(0.25*g)/(19*g*cm^-3xx25*cm^2)=5.26xx10^-4*1/(1/"cm")$

$5.26xx10^-4*cm-=5.26xx10^-3*mm$

What is the thickness of an iron plate that has a mass of 0.25*g0.25*g, and an area of 25*cm^225*cm^2. rho_"iron"=19*g*cm^-2rho_"iron"=19*g*cm^-2?