How is $"specific gravity"$ defined?

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Answer 1 · 2017-05-20T08:31:52

$"Specific gravity"=rho_"substance"/rho_"reference substance"$

And the $"reference substance"$ is typically water, for which under standard conditions, $rho_"water"=1*g*mL^-1$ , or $1*g*cm^-3$ .

And thus the product $rho_"water"xx"specific gravity"=rho_"substance"$ $=$ $0.67*g*cm^-3$ .

How is "specific gravity""specific gravity" defined?