Question #cd313

1 Answer
P dilip_k
Jun 2, 2017

specific gravity of the solution at a particular temperature (40^@C)

s="mass of the solution up to etched mark"/"mass of equal volume water"

=((20.3300 -20.23102)g)/((20.2376-20.23102)g)=0.09898/0.00658~~15

So density of the solution d=15g"/"mL at 40^@C

Related questions
See all questions in Density
Impact of this question
1657 views around the world
You can reuse this answer
Creative Commons License