Simplify #1024^(-4/5)#? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Jun 20, 2017 #1024^(-4/5)=1/256# Explanation: #1024^(-4/5)# = #(2xx2xx2xx2xx2xx2xx2xx2xx2xx2)^(-4/5)# = #(2^10)^(-4/5)# = #2^((10xx(-4/5))# = #2^(-8)# = #1/2^8# = #1/256# Answer link Related questions How do you simplify #c^3v^9c^-1c^0#? How do you simplify #(- 1/5)^-2 + (-2)^-2#? How do you simplify #(4^6)^2 #? How do you simplify #3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 #? How do you simplify #4^3ยท4^5#? How do you simplify #(5^-2)^-3#? How do you simplify and write #(-5.3)^0# with positive exponents? How do you factor #12j^2k - 36j^6k^6 + 12j^2#? How do you simplify the expression #2^5/(2^3 times 2^8)#? When can I add exponents? See all questions in Exponents Impact of this question 8841 views around the world You can reuse this answer Creative Commons License