Question #9cf1c

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Question #9cf1c

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Answer 1 · 2017-07-04T21:40:08

x = (2pi)/3,
x = (5pi)/3

Explanation:

Suggested solution --> possible error in question

$tan x + 1 = - \sqrt{3} (1 + cot x)$ $tan x + 1 = - sqrt3(1 + cot x)$
$\frac{tan x + 1}{\frac{1}{tan x} + 1} = - \sqrt{3}$ $(tan x + 1)/(1/tan x + 1) = - sqrt3$
Develop the left side
$\frac{(tan x + 1) (tan x)}{1 + tan x} = tan x$ $((tan x + 1)(tan x))/(1 + tan x) = tan x$
$tan x = - \sqrt{3}$ $tan x = - sqrt3$
Trig table and unit circle give:
$x = \frac{2 π}{3}$ $x = (2pi)/3$ and $x = \frac{2 π}{3} + π = \frac{5 π}{3}$ $x = (2pi)/3 + pi = (5pi)/3$

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Question #9cf1c

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