What is the derivative of $f(x)=1/3sec^3(2x)tan(2x)-2sec(2x)tan(2x)$ ?

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Answer 1 · 2017-07-16T06:40:16

$f'(x)=2sec^3(2x)tan(2x)-2sec(2x)tan(2x)$

Evaluate using the chain rule: $d/(dx)f(g(x))=f'(g(x))g'(x)$

$f(x)=1/3sec^3(2x)-sec(2x)$

$f'(x)=1/3(3)sec^2(2x)sec(2x)tan(2x)(2)-sec(2x)tan(2x)(2)$

Simplifying:

$=>f'(x)=2sec^3(2x)tan(2x)-2sec(2x)tan(2x)$

What is the derivative of f(x)=1/3sec^3(2x)tan(2x)-2sec(2x)tan(2x)f(x)=1/3sec^3(2x)tan(2x)-2sec(2x)tan(2x)?