Question #8d374

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Question #8d374

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Answer 1 · 2017-08-22T12:49:41

See a solution process below:

Explanation:

Because we are not allowed to divide by $0$ $0$ the excluded values for the expression: $\frac{5 x + 15}{x^{2} - 49}$ $(5x + 15)/(x^2 - 49)$ are $x^{2} - 49 \neq 0$ $x^2 - 49 != 0$

To find the values of $x$ $x$ where this exclusion is true we need to solve the denominator for $0$ $0$ :

$x^{2} - 49 = 0$ $x^2 - 49 = 0$

$x^{2} - 49 + 49 = 0 + 49$ $x^2 - 49 + color(red)(49) = 0 + color(red)(49)$

$x^{2} - 0 = 49$ $x^2 - 0 = 49$

$x^{2} = 49$ $x^2 = 49$

$\sqrt{x^{2}} = \pm \sqrt{49}$ $sqrt(x^2) = +-sqrt(49)$

$x = \pm 7$ $x = +-7$

The excluded values are: $x \neq - 7$ $x != -7$ and $x \neq 7$ $x != 7$

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Question #8d374

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