Question #2f5c5

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Question #2f5c5

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Answer 1 · 2017-12-24T07:12:13

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Explanation:

$27000 k g \cdot m^{- 3}$ $27000" "kg cdot m^-3$
$= 27000 \times 1 k g \times 1 m^{- 3}$ $=27000xx1" "kgxx1" "m^-3$
$= 27000 \times 1000 g m \times {(\frac{1}{100})}^{3} c m^{- 3}$ $=27000xx1000" "gmxx(1/100)^3" "cm^-3$
$= 27000 \times 1000 \times \frac{1}{1000000} g m \cdot c m^{- 3}$ $=27000xx1000xx1/1000000" "gmcdotcm^-3$
$= 27 g m \cdot c m^{- 3}$ $=27" "gmcdotcm^-3$

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