Question #a04c1
1 Answer
Explanation:
Your goal here is to write your number in normalized scientific notation, which has
color(white)(aa)color(blue)(m) xx 10^(color(purple)(n) color(white)(a)stackrel(color(white)(aaaaaa))(larr))color(white)(acolor(black)("the")acolor(purple)("exponent")aa)aam×10naaaaaaa←−−−atheaexponentaa
color(white)(a/acolor(black)(uarr)aaaa)aa↑⏐ ⏐⏐aaaa
color(white)(color(black)("the")acolor(blue)("mantissa")a)theamantissaa
and
1 <= |color(blue)(m)| < 10" " " "color(darkorange)("(*)")1≤|m|<10 (*)
As you know, you have
10^0 = 1100=1
This means that you can write your initial number as
color(blue)(0.00456) * 10^color(purple)(0)0.00456⋅100
Now, to start converting the number to scientific notation, multiply it by
color(blue)(0.00456) * 10^color(purple)(0) * color(blue)(10)/color(purple)(10)0.00456⋅100⋅1010
You can rewrite this as
color(blue)(0.00456) * color(blue)(10) * 10^color(purple)(0)/color(purple)(10) = color(blue)(0.0456) * 10^color(purple)(-1)0.00456⋅10⋅10010=0.0456⋅10−1
At this point, you must check to see if the new value of the mantissa satisfies condition
Since
1 color(red)(cancel(color(black)(<=))) color(blue)(0.0456) color(red)(cancel(color(black)(<))) 10
you must repeat the process again. This time, you have
color(blue)(0.0456) * 10^color(purple)(-1) * color(blue)(10)/color(purple)(10)
which is equivalent to
color(blue)(0.0456) * color(blue)(10) * 10^color(purple)(-1)/color(purple)(10) = color(blue)(0.456) * 10^color(purple)(-2)
Condition
color(blue)(0.456) * 10^color(purple)(-2) * color(blue)(10)/color(purple)(10)
which is equivalent to
color(blue)(0.456) * color(blue)(10) * 10^color(purple)(-2)/color(purple)(10) = color(blue)(4.56) * 10^color(purple)(-3)
Finally, you have
1 <= color(blue)(4.56) < 10" " " "color(darkgreen)(sqrt())
so you can say that
color(darkgreen)(ul(color(black)(0.00456 = 4.56 * 10^(-3))))
Notice that the number written in scientific notation has
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