Question #1340d

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Question #1340d

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Answer 1 · 2017-09-08T15:21:12

$m = \frac{P t}{g h}$ $m=(Pt)/(gh)$

Explanation:

$P = \frac{m g h}{t}$ $P=(mgh)/t$

$\frac{P}{1} = \frac{m g h}{t}$ $P/1 = (mgh)/t$

Now cross multiply $t$ $t$ with $P$ $P$ and multiply $1$ $1$ with $m g h$ $mgh$ . Then, take $m$ $m$ as common multiple and make a fraction form by dividing

$m = \frac{P t}{g h}$ $m = (Pt)/(gh)$

Answer 2 · 2017-09-09T16:43:35

We assume that the symbols used in the equation

$P = \frac{m g h}{t}$ $P=(mgh)/t$
are $P$ $P$ Power, as power is the rate of doing work.
$t$ $t$ time
$m g h$ $mgh$ potential energy due to gravity

As such $m =$ $m=$ mass of the object under consideration.

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Question #1340d

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